C-11-Q064mediumsingle_mcqIf a:b=b:ca:b = b:ca:b=b:c, then a2+b2b2+c2\dfrac{a^2 + b^2}{b^2 + c^2}b2+c2a2+b2 equals—aac\dfrac{a}{c}cabbc\dfrac{b}{c}cbcca\dfrac{c}{a}acd111ব্যাখ্যাSince a:b=b:ca:b=b:ca:b=b:c, set ab=bc=k\dfrac{a}{b}=\dfrac{b}{c}=kba=cb=k, so b2=acb^2=acb2=ac and a=bk, b=cka=bk,\ b=cka=bk, b=ck. Then a2+b2b2+c2=k2(b2+c2)b2+c2=k2=ac\dfrac{a^2+b^2}{b^2+c^2}=\dfrac{k^2(b^2+c^2)}{b^2+c^2}=k^2=\dfrac{a}{c}b2+c2a2+b2=b2+c2k2(b2+c2)=k2=ca, because ac=ab⋅bc=k2\dfrac{a}{c}=\dfrac{a}{b}\cdot\dfrac{b}{c}=k^2ca=ba⋅cb=k2.