C-11-Q058mediumsingle_mcq

From $\dfrac{a}{b} = \dfrac{c}{d}$ , the value of $\dfrac{a^2+b^2}{a^2-b^2}$ is—

a $\dfrac{ac+bd}{ac-bd}$
b $\dfrac{c+d}{c-d}$
c $\dfrac{a+b}{a-b}$
d $1$

ব্যাখ্যা

With $\dfrac{a}{b}=\dfrac{c}{d}$ , set $a=ck,\ b=dk$ . Then $a^2+b^2=k^2(c^2+d^2)$ and $a^2-b^2=k^2(c^2-d^2)$ , while $ac+bd=k(c^2+d^2)$ and $ac-bd=k(c^2-d^2)$ , so $\dfrac{a^2+b^2}{a^2-b^2}=\dfrac{ac+bd}{ac-bd}$ .

এই অধ্যায়ের আরও প্রশ্ন

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Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

From $\dfrac{a}{b} = \dfrac{c}{d}$ , the value of $\dfrac{a^2+b^2}{a^2-b^2}$ is—

\dfrac{ac+bd}{ac-bd}

\dfrac{c+d}{c-d}

\dfrac{a+b}{a-b}

1

From ab=cd\dfrac{a}{b} = \dfrac{c}{d}ba​=dc​, the value of a2+b2a2−b2\dfrac{a^2+b^2}{a^2-b^2}a2−b2a2+b2​ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From ab=cd\dfrac{a}{b} = \dfrac{c}{d}ba​=dc​, the value of a2+b2a2−b2\dfrac{a^2+b^2}{a^2-b^2}a2−b2a2+b2​ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From $\dfrac{a}{b} = \dfrac{c}{d}$ , the value of $\dfrac{a^2+b^2}{a^2-b^2}$ is—

From $\dfrac{a}{b} = \dfrac{c}{d}$ , the value of $\dfrac{a^2+b^2}{a^2-b^2}$ is—