C-03-Q150mediumsingle_mcqFactorize a3+3a+36a^3 + 3a + 36a3+3a+36:a(a+3)(a2−3a+12)(a+3)(a^2 - 3a + 12)(a+3)(a2−3a+12)b(a−3)(a2+3a+12)(a-3)(a^2 + 3a + 12)(a−3)(a2+3a+12)c(a+3)3(a+3)^3(a+3)3d(a+3)(a2+3a+12)(a+3)(a^2 + 3a + 12)(a+3)(a2+3a+12)ব্যাখ্যাSubstituting a=−3a=-3a=−3 gives −27−9+36=0-27 - 9 + 36 = 0−27−9+36=0, so (a+3)(a+3)(a+3) is a factor. Dividing a3+3a+36a^3 + 3a + 36a3+3a+36 by (a+3)(a+3)(a+3) produces a2−3a+12a^2 - 3a + 12a2−3a+12.