C-03-Q154mediumsingle_mcqFactorize a3−7a2b+7ab2−b3a^3 - 7a^2 b + 7ab^2 - b^3a3−7a2b+7ab2−b3:a(a−b)(a2−6ab+b2)(a-b)(a^2 - 6ab + b^2)(a−b)(a2−6ab+b2ব্যাখ্যাSetting a=ba=ba=b gives b3−7b3+7b3−b3=0b^3 - 7b^3 + 7b^3 - b^3 = 0b3−7b3+, so is a factor. Dividing the homogeneous expression by yields .