C-03-Q154mediumsingle_mcqFactorize a3−7a2b+7ab2−b3a^3 - 7a^2 b + 7ab^2 - b^3a3−7a2b+7ab2−b3:a(a−b)(a2−6ab+b2)(a-b)(a^2 - 6ab + b^2)(a−b)(a2−6ab+b2)b(a−b)3(a-b)^3(a−b)3c(a−b)(a2+6ab+b2)(a-b)(a^2 + 6ab + b^2)(a−b)(a2+6ab+b2)d(a+b)(a2−6ab+b2)(a+b)(a^2 - 6ab + b^2)(a+b)(a2−6ab+b2)ব্যাখ্যাSetting a=ba=ba=b gives b3−7b3+7b3−b3=0b^3 - 7b^3 + 7b^3 - b^3 = 0b3−7b3+7b3−b3=0, so (a−b)(a-b)(a−b) is a factor. Dividing the homogeneous expression by (a−b)(a-b)(a−b) yields a2−6ab+b2a^2 - 6ab + b^2a2−6ab+b2.