C-03-Q157mediumsingle_mcqFactorize 4a3−5a2+5a−14a^3 - 5a^2 + 5a - 14a3−5a2+5a−1:a(4a−1)(a2−a+1)(4a-1)(a^2 - a + 1)(4a−1)(a2−a+1)b(4a+1)(a2+a+1)(4a+1)(a^2 + a + 1)(4a+1)(a2+a+1)c(4a−1)(a2+a+1)(4a-1)(a^2 + a + 1)(4a−1)(a2+a+1)d(a−1)(4a2−a+1)(a-1)(4a^2 - a + 1)(a−1)(4a2−a+1)ব্যাখ্যাTesting a=14a=\tfrac14a=41 gives zero, so (4a−1)(4a-1)(4a−1) is a factor. Dividing 4a3−5a2+5a−14a^3 - 5a^2 + 5a - 14a3−5a2+5a−1 by (4a−1)(4a-1)(4a−1) leaves a2−a+1a^2 - a + 1a2−a+1.