C-03-Q122mediumsingle_mcqFactorize 3(a2+2a)2−22(a2+2a)+403(a^2 + 2a)^2 - 22(a^2 + 2a) + 403(a2+2a)2−22(a2+2a)+40:a(3a2+6a−10)(a2+2a−4)(3a^2 + 6a - 10)(a^2 + 2a - 4)(3a2+6a−10)(a2+ব্যাখ্যাTreating u=a2+2au = a^2+2au=a2+2a gives 3u2−22u+40=(3u−10)(u−4)3u^2 - 22u + 40 = (3u-10)(u-4)3u since split of works with product . Substituting back yields .