C-03-Q081mediumsingle_mcqWith same data, a3+1a3=?a^3 + \dfrac{1}{a^3} = ?a3+a31=?a18318\sqrt{3}183b24324\sqrt{3}243c636\sqrt{3}63d838\sqrt{3}83ব্যাখ্যাHere a+1a=23a+\dfrac1a=2\sqrt3a+a1=23, so using a3+1a3=(a+1a)3−3(a+1a)a^3+\dfrac1{a^3}=\left(a+\dfrac1a\right)^3-3\left(a+\dfrac1a\right)a3+a31=(a+a1)3−3(a+a1) gives (23)3−3(23)=243−63=183(2\sqrt3)^3-3(2\sqrt3)=24\sqrt3-6\sqrt3=18\sqrt3(23)3−3(23)=243−63=183.