C-03-Q082mediumsingle_mcqIf x+y=5x+y=5x+y=5 and xy=6xy=6xy=6, 2(x2+y2)=?2(x^2+y^2) = ?2(x2+y2)=?a262626b131313c505050d363636ব্যাখ্যাSince x2+y2=(x+y)2−2xy=25−12=13x^2+y^2=(x+y)^2-2xy=25-12=13x2+y2=(x+y)2−2xy=25−12=13, doubling gives 2(x2+y2)=2×13=262(x^2+y^2)=2\times13=262(x2+y2)=2×13=26.