C-03-Q080mediumsingle_mcqIf a=3+2a = \sqrt{3} + \sqrt{2}a=3+2, a+1a=?a + \dfrac{1}{a} = ?a+a1=?a232\sqrt{3}23b5\sqrt{5}ব্যাখ্যাRationalizing, 1a=13+2=3−2\frac1a=\frac1{\sqrt3+\sqrt2}=\sqrt3-\sqrt2a1=3, so .