C-03-Q041mediumsingle_mcqIf a+b+c=15a+b+c=15a+b+c=15 and a2+b2+c2=83a^2+b^2+c^2=83a2+b2+c2=83, ab+bc+ca=?ab+bc+ca = ?ab+bc+ca=?a717171b142142142c353535d505050ব্যাখ্যাUsing (a+b+c)2=a2+b2+c2+2(ab+bc+ca)(a+b+c)^2 = a^2+b^2+c^2 + 2(ab+bc+ca)(a+b+c)2=a2+b2+c2+2(ab+bc+ca), we get 152=83+2(ab+bc+ca)15^2 = 83 + 2(ab+bc+ca)152=83+2(ab+bc+ca), so 225−83=142=2(ab+bc+ca)225-83=142=2(ab+bc+ca)225−83=142=2(ab+bc+ca). Dividing by 2 gives ab+bc+ca=71ab+bc+ca = 71ab+bc+ca=71.