C-03-Q039mediumsingle_mcqWith same data, ab=?ab = ?ab=?a000b111c222d333ব্যাখ্যাSubtracting the equations, (a2+ab+b2)−(a2−ab+b2)=3−1(a^2+ab+b^2)-(a^2-ab+b^2)=3-1(a2+ab+b2)−(a2−ab+b2)=3−1 gives 2ab=22ab=22ab=2, so ab=1ab=1ab=1.