After cross-multiplication in $\dfrac{240}{x + 1} = \dfrac{240 - x}{x}$ (Shahik's pens), the resulting equation in $x$ i

Question

After cross-multiplication in $\dfrac{240}{x + 1} = \dfrac{240 - x}{x}$ (Shahik's pens), the resulting equation in $x$ is—

Accepted Answer

$x^2 + x - 240 = 0$

Answer

$x^2 - x - 240 = 0$

Answer

$x^2 + x + 240 = 0$

Answer

$x^2 - 240x = 0$

After cross-multiplication in 240x+1=240−xx\dfrac{240}{x + 1} = \dfrac{240 - x}{x}x+1240​=x240−x​ (Shahik's pens), the resulting equation in xxx is—