The substitution method for $\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0$ uses—

Question

Accepted Answer

letting $y = \dfrac{x + a}{x - a}$ to reduce to quadratic in $y$

Answer

completing square

Answer

squaring both sides

Answer

cross-multiplication only

The substitution method for (x+ax−a)2−5(x+ax−a)+6=0\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0(x−ax+a​)2−5(x−ax+a​)+6=0 uses—