C-11-Q164mediumsingle_mcqIf x2+y2xy=y2+z2yz\dfrac{x^2 + y^2}{xy} = \dfrac{y^2 + z^2}{yz}xyx2+y2=yzy2+z2 and z≠xz \ne xz=x, then x,y,zx, y, zx,y,z are in—aarithmetic progressionbcontinued proportioncgeometric progressiondequal