If $\dfrac{a^3+b^3}{a-b+c} = a(a+b)$, then—

Question

Accepted Answer

$a, b, c$ are in continued proportion

Answer

$a, b, c$ are in arithmetic progression

Answer

$a + b + c = 0$

Answer

$abc = 1$

If a3+b3a−b+c=a(a+b)\dfrac{a^3+b^3}{a-b+c} = a(a+b)a−b+ca3+b3​=a(a+b), then—