C-11-Q069mediumsingle_mcqIf x2=y3=z5\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z}{5}2x=3y=5z, then x+y+z2+3+5\dfrac{x+y+z}{2+3+5}2+3+5x+y+z equals—ax2\dfrac{x}{2}2xb110\dfrac{1}{10}