C-11-Q058mediumsingle_mcqFrom ab=cd\dfrac{a}{b} = \dfrac{c}{d}ba=dc, the value of a2+b2a2−b2\dfrac{a^2+b^2}{a^2-b^2}a2−b2a2+ is—aac+bdac−bd\dfrac{ac+bd}{ac-bd}ac−bdac+bdb