C-08-Q159mediumsingle_mcqSolve for θ\thetaθ in π2<θ<2π\dfrac{\pi}{2} < \theta < 2\pi2π<θ<2π: tanθ=−3\tan\theta = -\sqrt{3}tanθ=−3. The values are —a2π3\dfrac{2\pi}{3}32π onlyb5π3\dfrac{5\pi}{3} only