With $ an heta = \dfrac{5}{12}$ and $\cos heta$ negative, the value of $\dfrac{\sin heta+\cos(- heta)}{\sec(- heta

Question

With $	an	heta = \dfrac{5}{12}$ and $\cos	heta$ negative, the value of $\dfrac{\sin	heta+\cos(-	heta)}{\sec(-	heta)+	an	heta}$ is —

Accepted Answer

$\dfrac{51}{26}$

Answer

$-\dfrac{51}{26}$

Answer

$\dfrac{17}{26}$

Answer

$\dfrac{26}{51}$

With tan⁡θ=512\tan\theta = \dfrac{5}{12}tanθ=125​ and cos⁡θ\cos\thetacosθ negative, the value of sin⁡θ+cos⁡(−θ)sec⁡(−θ)+tan⁡θ\dfrac{\sin\theta+\cos(-\theta)}{\sec(-\theta)+\tan\theta}sec(−θ)+tanθsinθ+cos(−θ)​ is —