C-08-Q066mediumsingle_mcqcosθ\cos\thetacosθ equals —abasehypotenuse\dfrac{\text{base}}{\text{hypotenuse}}hypotenusebasebperpendicularhypotenuse\dfrac{\text{perpendicular}}{\text{hypotenuse}}hypotenuseperpendicularcbaseperpendicular\dfrac{\text{base}}{\text{perpendicular}}perpendicularbasedhypotenusebase\dfrac{\text{hypotenuse}}{\text{base}}basehypotenuse