C-08-Q065mediumsingle_mcqIn a right-angled triangle with acute angle θ\thetaθ, sinθ\sin\thetasinθ equals —abasehypotenuse\dfrac{\text{base}}{\text{hypotenuse}}hypotenusebasebperpendicularhypotenuse\dfrac{\text{perpendicular}}{\text{hypotenuse}}hypotenuseperpendicularcperpendicularbase\dfrac{\text{perpendicular}}{\text{base}}baseperpendiculardhypotenusebase\dfrac{\text{hypotenuse}}{\text{base}}basehypotenuse