In $ riangle ABC$, $BE$ and $CF$ are perpendiculars on $AC$ and $AB$ respectively. Then $\dfrac{ riangle ABC}{ riangl

Question

In $	riangle ABC$, $BE$ and $CF$ are perpendiculars on $AC$ and $AB$ respectively. Then $\dfrac{	riangle ABC}{	riangle AEF} =$

Accepted Answer

$\dfrac{AB^2}{AE^2}$

Answer

$\dfrac{AB}{AE}$

Answer

$\dfrac{AE}{AB}$

Answer

$\dfrac{AC}{AE}$

In △ABC\triangle ABC△ABC, BEBEBE and CFCFCF are perpendiculars on ACACAC and ABABAB respectively. Then △ABC△AEF=\dfrac{\triangle ABC}{\triangle AEF} =△AEF△ABC​=