The bisector of $\angle A$ of $ riangle ABC$ meets $BC$ at $D$ and the circumcircle at $E$. Then $AD^2 =$

Question

The bisector of $\angle A$ of $	riangle ABC$ meets $BC$ at $D$ and the circumcircle at $E$. Then $AD^2 =$

Accepted Answer

$AB \cdot AC - BD \cdot DC$

Answer

$AB \cdot AC + BD \cdot DC$

Answer

$AB \cdot BD - AC \cdot DC$

Answer

$AB \cdot AC$

The bisector of ∠A\angle A∠A of △ABC\triangle ABC△ABC meets BCBCBC at DDD and the circumcircle at EEE. Then AD2=AD^2 =AD2=