In $ riangle ABC$, side $BC$ is trisected at points $P$ and $Q$. Then $AB^2 + AC^2 =$

Question

In $	riangle ABC$, side $BC$ is trisected at points $P$ and $Q$. Then $AB^2 + AC^2 =$

Accepted Answer

$AP^2 + AQ^2 + 4 PQ^2$

Answer

$AP^2 + AQ^2 + PQ^2$

Answer

$2(AP^2 + AQ^2)$

Answer

$AP^2 + AQ^2 + 2 PQ^2$

In △ABC\triangle ABC△ABC, side BCBCBC is trisected at points PPP and QQQ. Then AB2+AC2=AB^2 + AC^2 =AB2+AC2=