C-03-Q038mediumsingle_mcqIn △ABC\triangle ABC△ABC, ADADAD is the perpendicular on BCBCBC and BEBEBE is the perpendicular on ACACAC. Then —aBC⋅CD=AC⋅CEBC \cdot CD = AC \cdot CEBC⋅CD=AC⋅CEbBC⋅CD=AB⋅AEBC \cdot CD = AB \cdot AE