C-02-Q070mediumsingle_mcq∣A∪B∣=?|A \cup B| = ?∣A∪B∣=?a∣A∣+∣B∣|A| + |B|∣A∣+∣B∣b∣A∣+∣B∣−∣A∩B∣|A| + |B| - |A \cap B|∣A∣+∣B∣−∣A∩B∣c∣A∣⋅∣B∣|A| \cdot |B|∣A∣⋅∣B∣d∣A∣−∣B∣|A| - |B|∣A∣−∣B∣