$\dfrac{x + 5}{(x - 1)(x - 2)(x - 3)} = \dfrac{A}{x - 1} + \dfrac{B}{x - 2} + \dfrac{C}{x - 3}$ হলে $(A, B, C)$ কত?

Question

Accepted Answer

$(3, -7, 4)$

Answer

$(-3, 7, -4)$

Answer

$(3, 7, 4)$

Answer

$(-3, -7, -4)$

x+5(x−1)(x−2)(x−3)=Ax−1+Bx−2+Cx−3\dfrac{x + 5}{(x - 1)(x - 2)(x - 3)} = \dfrac{A}{x - 1} + \dfrac{B}{x - 2} + \dfrac{C}{x - 3}(x−1)(x−2)(x−3)x+5​=x−1 হলে (A,B,C)(A, B, C)(A,B,C) কত?