C-09-Q185mediumsingle_mcq

If $\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}$ , then $A = ?$

a $30^\circ$
b $45^\circ$
c $60^\circ$
d $75^\circ$

ব্যাখ্যা

Dividing numerator and denominator by $\cos A$ gives $\dfrac{1-\tan A}{1+\tan A}=\dfrac{1-\sqrt3}{1+\sqrt3}$ , so $\tan A=\sqrt3$ . The acute angle with this tangent is $60^\circ$ .

এই অধ্যায়ের আরও প্রশ্ন

C-09-Q186Solve: , acute.
C-09-Q187Solve: , acute.
C-09-Q188Solve: , .
C-09-Q189Solve: , acute.
C-09-Q190Solve: .
C-09-Q191If and with acute, then
C-09-Q192With the same data,
C-09-Q193If and with acute, then
C-09-Q194With the same data,
C-09-Q195If and with acute, then

Trigonometric Ratio — সব প্রশ্ন দেখুন (217টি) →

If $\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}$ , then $A = ?$

30^\circ

45^\circ

60^\circ

75^\circ

ব্যাখ্যা

Dividing numerator and denominator by $\cos A$ gives $\dfrac{1-\tan A}{1+\tan A}=\dfrac{1-\sqrt3}{1+\sqrt3}$ , so $\tan A=\sqrt3$ . The acute angle with this tangent is $60^\circ$ .

If cos⁡A−sin⁡Acos⁡A+sin⁡A=1−31+3\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}cosA+sinAcosA−sinA​=1+3​1−3​​, then A=?A = ?A=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If cos⁡A−sin⁡Acos⁡A+sin⁡A=1−31+3\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}cosA+sinAcosA−sinA​=1+3​1−3​​, then A=?A = ?A=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}$ , then $A = ?$

If $\dfrac{\cos A - \sin A}{\cos A + \sin A} = \dfrac{1 - \sqrt{3}}{1 + \sqrt{3}}$ , then $A = ?$