C-09-Q178mediumsingle_mcqtan30∘⋅tan60∘=?\tan 30^\circ \cdot \tan 60^\circ = ?tan30∘⋅tan60∘=?a000b111c3\sqrt{3}3d13\dfrac{1}{3}31ব্যাখ্যাtan30∘=13\tan 30^\circ=\tfrac{1}{\sqrt3}tan30∘=31 and tan60∘=3\tan 60^\circ=\sqrt3tan60∘=3 are reciprocals, so their product is 111. (They satisfy tanθ⋅tan(90∘−θ)=1\tan\theta\cdot\tan(90^\circ-\theta)=1tanθ⋅tan(90∘−θ)=1.)