C-09-Q057mediumsingle_mcq1−cos2θ=?1 - \cos^2\theta = ?1−cos2θ=?asin2θ\sin^2\thetasin2θbtan2θ\tan^2\thetatan2θccosec2θ\operatorname{cosec}^2\thetacosec2θdsec2θ\sec^2\thetasec2θব্যাখ্যাFrom sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1, subtracting cos2θ\cos^2\thetacos2θ gives sin2θ=1−cos2θ\sin^2\theta = 1 - \cos^2\thetasin2θ=1−cos2θ.