C-02-Q128mediumsingle_mcqIf f(x)=x2−4x+3f(x) = x^2 - 4x + 3f(x)=x2−4x+3, then f(−1)=f(-1) =f(−1)=a000b222c666d888ব্যাখ্যাSubstituting x=−1x=-1x=−1: f(−1)=(−1)2−4(−1)+3=1+4+3=8f(-1)=(-1)^2-4(-1)+3=1+4+3=8f(−1)=(−1)2−4(−1)+3=1+4+3=8.