C-02-Q133: If $f(x) = x^3 - 6x^2 + 11x - 6$, then $f(x) = 0$ for $x =$ | প্রশ্ন করি

C-02-Q133mediumsingle_mcq

If $f(x) = x^3 - 6x^2 + 11x - 6$ , then $f(x) = 0$ for $x =$

Factoring, $x^3-6x^2+11x-6=(x-1)(x-2)(x-3)$ , so the roots are . Each value satisfies .

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-

2

,

-

3

-1, -2, -3

- 1, - 2, - 3

2, 3, 4

(x−

1)(x−

2)(x−

x=1,2,3

f(x)=0