C-02-Q120mediumsingle_mcqIf A={0,1,2,3}A = \{0, 1, 2, 3\}A={0,1,2,3} and R={(x,y):x,y∈A,y=x+1}R = \{(x, y) : x, y \in A, y = x + 1\}R={(x,y):x,y∈A,y=x+1}, then R=R =R=a{(0,1),(1,2),(2,3),(3,4)}\{(0, 1), (1, 2), (2, 3), (3, 4)\}{(0,1),(1,2),(2,3),(3,4)}b{(0,1),(1,2),(2,3)}\{(0, 1), (1, 2), (2, 3)\}{(0,1),(1,2),(2,3)}c{(1,0),(2,1),(3,2)}\{(1, 0), (2, 1), (3, 2)\}{(1,0),(2,1),(3,2)}d{(0,0),(1,1),(2,2)}\{(0, 0), (1, 1), (2, 2)\}{(0,0),(1,1),(2,2)}ব্যাখ্যাApplying y=x+1y=x+1y=x+1 with both x,y∈A={0,1,2,3}x,y\in A=\{0,1,2,3\}x,y∈A={0,1,2,3}: x=0,1,2x=0,1,2x=0,1,2 give y=1,2,3y=1,2,3y=1,2,3, all in AAA, but x=3x=3x=3 gives y=4∉Ay=4\notin Ay=4∈/A and is excluded. So R={(0,1),(1,2),(2,3)}R=\{(0,1),(1,2),(2,3)\}R={(0,1),(1,2),(2,3)}.