C-14-Q093mediumsingle_mcq

With $DE \parallel BC$ , the area ratio is —

a $\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC}{DE}$
b $\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC^{2}}{DE^{2}}$
c $\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{DE^{2}}{BC^{2}}$
d $\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{AD}{AB}$

ব্যাখ্যা

The ratio of areas of two similar triangles equals the square of the ratio of any pair of corresponding sides. Since $BC$ and $DE$ are corresponding sides, $\frac{\triangle ABC}{\triangle ADE} = \frac{BC^{2}}{DE^{2}}$ .

এই অধ্যায়ের আরও প্রশ্ন

\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC}{DE}

\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC^{2}}{DE^{2}}

\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{DE^{2}}{BC^{2}}

\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{AD}{AB}

With DE∥BCDE \parallel BCDE∥BC, the area ratio is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With DE∥BCDE \parallel BCDE∥BC, the area ratio is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With $DE \parallel BC$ , the area ratio is —

With $DE \parallel BC$ , the area ratio is —