C-14-Q099mediumsingle_mcq

In Exercise 14.2 Q11, $\triangle ABC : \triangle DEF$ when $\angle A = \angle D$ equals —

a $AB:DE$
b $AB \cdot AC : DE \cdot DF$
c $BC^{2}:EF^{2}$
d $AB+AC:DE+DF$

ব্যাখ্যা

With $\angle A = \angle D$ , the areas of the triangles are proportional to the products of the sides enclosing the equal angle. Thus $\triangle ABC : \triangle DEF = AB \cdot AC : DE \cdot DF$ .

এই অধ্যায়ের আরও প্রশ্ন

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In Exercise 14.2 Q11, $\triangle ABC : \triangle DEF$ when $\angle A = \angle D$ equals —

AB:DE

AB \cdot AC : DE \cdot DF

BC^{2}:EF^{2}

AB+AC:DE+DF

ব্যাখ্যা

With $\angle A = \angle D$ , the areas of the triangles are proportional to the products of the sides enclosing the equal angle. Thus $\triangle ABC : \triangle DEF = AB \cdot AC : DE \cdot DF$ .

In Exercise 14.2 Q11, △ABC:△DEF\triangle ABC : \triangle DEF△ABC:△DEF when ∠A=∠D\angle A = \angle D∠A=∠D equals —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Exercise 14.2 Q11, △ABC:△DEF\triangle ABC : \triangle DEF△ABC:△DEF when ∠A=∠D\angle A = \angle D∠A=∠D equals —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Exercise 14.2 Q11, $\triangle ABC : \triangle DEF$ when $\angle A = \angle D$ equals —

In Exercise 14.2 Q11, $\triangle ABC : \triangle DEF$ when $\angle A = \angle D$ equals —