C-16-Q038mediumsingle_mcq

With $AB=15$ , $BC=20$ , $AC=25$ and $BD\perp AC$ , the length $BD$ equals —

The altitude to the hypotenuse equals the product of the legs divided by the hypotenuse: $BD=\dfrac{AB\cdot BC}{AC}=\dfrac{15\times20}{25}=12$ .

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16

2515×20=