C-16-Q046mediumsingle_mcq

Two persons walk along roads making $135°$ at $7$ km/h and $5$ km/h for $4$ hours. The square of the direct distance (km²) is approximately —

The distances are $28$ km and $20$ km with included angle $135°$ . Then $d^2=28^2+20^2-2(28)(20)\cos135°\approx1184+792\approx1976$ .

46/210

এই অধ্যায়ের আরও প্রশ্ন

C-16-Q047Length of rectangle is , breadth . Its area is —
C-16-Q048Perimeter of a rectangle of length and breadth is —
C-16-Q049Diagonal of a rectangle of length and breadth is —
C-16-Q050Length of a rectangular room is of its breadth. Area is sq m. Breadth is —
C-16-Q051With area sq m and length breadth, length equals —
C-16-Q052The perimeter of the rectangle in the above problem is —
C-16-Q053Approximate length of diagonal of a rectangle of m by m is —
C-16-Q054Area of a rectangle is sq m. If length is reduced by m it becomes a square. The length and breadth are —
C-16-Q055Area of a rectangle is sq m. If length is reduced by m it becomes a square. The breadth is —

2456

282+

202−

2(28)(20)cos135°≈

1184+

792≈

1976