C-16-Q029mediumsingle_mcq

For an isosceles triangle with equal sides $a$ and base $b$ , the height from the apex to the base is —

a $\dfrac{1}{2}\sqrt{4a^2 - b^2}$
b $\sqrt{a^2 - b^2}$
c $\dfrac{1}{2}\sqrt{a^2 - b^2}$
d $\dfrac{b}{2}$

ব্যাখ্যা

The apex height drops perpendicularly to the midpoint of the base, creating a right triangle with hypotenuse $a$ and half-base $\frac{b}{2}$ . The height is $\sqrt{a^2 - \frac{b^2}{4}} = \frac{1}{2}\sqrt{4a^2 - b^2}$ .

এই অধ্যায়ের আরও প্রশ্ন

Chapter 16: Mensuration — সব প্রশ্ন দেখুন (210টি) →

For an isosceles triangle with equal sides $a$ and base $b$ , the height from the apex to the base is —

\dfrac{1}{2}\sqrt{4a^2 - b^2}

\sqrt{a^2 - b^2}

\dfrac{1}{2}\sqrt{a^2 - b^2}

\dfrac{b}{2}

For an isosceles triangle with equal sides aaa and base bbb, the height from the apex to the base is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

For an isosceles triangle with equal sides aaa and base bbb, the height from the apex to the base is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

For an isosceles triangle with equal sides $a$ and base $b$ , the height from the apex to the base is —

For an isosceles triangle with equal sides $a$ and base $b$ , the height from the apex to the base is —