C-13-Q106mediumsingle_mcqWith first term 272727 and common ratio 13\dfrac{1}{3}31, the tenth term is —a1243\dfrac{1}{243}2431b1729\dfrac{1}{729}7291c12187\dfrac{1}{2187}21871d181\dfrac{1}{81}811ব্যাখ্যাThe tenth term is 27(13)9=33⋅3−9=3−6=172927\left(\tfrac13\right)^{9}=3^{3}\cdot 3^{-9}=3^{-6}=\dfrac{1}{729}27(31)9=33⋅3−9=3−6=7291.