C-04-Q235mediumsingle_mcq5logab+5logbc+5logca=?5 \log\dfrac{a}{b} + 5\log\dfrac{b}{c} + 5\log\dfrac{c}{a} = ?5logba+5logcb+5logac=?a000b111c555dlogabব্যাখ্যাThe arguments multiply to ab⋅bc⋅ca=1\dfrac{a}{b}\cdot\dfrac{b}{c}\cdot\dfrac{c}{a} = 1ba⋅cb, so the sum of logs is .