C-04-Q234mediumsingle_mcq3⋅2n+1−4⋅2n−12n+2=?\dfrac{3 \cdot 2^{n+1} - 4 \cdot 2^{n-1}}{2^{n+2}} = ?2n+23⋅2n+1−4⋅2n−1=?a12\dfrac{1}{2}21b54\dfrac{5}{4}4ব্যাখ্যাFactor out 2n−12^{n-1}2n−1 from the numerator: 3⋅2n+1−4⋅2n−1=2n−1(3⋅4−4)=2n−1⋅8=2n+23\cdot2^{n+1} - 4\cdot2^{n-1} = 2^{n-1}(3\cdot4 - 4) = 2^{n-1}\cdot 8 = 2^{n+2}3⋅. Dividing by gives .