C-04-Q161mediumsingle_mcqSolve log5x=−2\log_5 x = -2log5x=−2 (Ex 4.2 Q2):ax=−25x = -25x=−25bx=125x = \dfrac{1}{25}x=251ব্যাখ্যাlog5x=−2\log_5 x = -2log5x=−2 means x=5−2=152=125x = 5^{-2} = \dfrac{1}{5^2} = \dfrac{1}{25}x=5. A logarithm equation is solved by rewriting it in exponential form.