C-04-Q160mediumsingle_mcqSolve logx25=2\log_x 25 = 2logx25=2 (Ex 4.2 Q2):ax=5x = 5x=5bx=−5x = -5x=−5cx=±5x = \pm 5x=±5dx=25x = 25x=25ব্যাখ্যাlogx25=2\log_x 25 = 2logx25=2 means x2=25x^2 = 25x2=25. Since a logarithm base must be positive, only x=5x = 5x=5 is valid.