C-05-Q068mediumsingle_mcq

Solve $\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}$ :

a $\dfrac{a^2 - b^2}{a^2 + b^2}$
b $\dfrac{a + b}{a - b}$
c $\dfrac{a - b}{a + b}$
d $\dfrac{ab}{a^2 + b^2}$

ব্যাখ্যা

Combining the left side, $\left(\dfrac{a^2+b^2}{ab}\right)x = \dfrac{a^2-b^2}{ab}$ ; the common $ab$ cancels, leaving $x = \dfrac{a^2 - b^2}{a^2 + b^2}$ .

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

Solve $\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}$ :

\dfrac{a^2 - b^2}{a^2 + b^2}

\dfrac{a + b}{a - b}

\dfrac{a - b}{a + b}

\dfrac{ab}{a^2 + b^2}

ব্যাখ্যা

Combining the left side, $\left(\dfrac{a^2+b^2}{ab}\right)x = \dfrac{a^2-b^2}{ab}$ ; the common $ab$ cancels, leaving $x = \dfrac{a^2 - b^2}{a^2 + b^2}$ .

Solve abx+bax=a2−b2ab\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}ba​x+ab​x=aba2−b2​:

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solve abx+bax=a2−b2ab\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}ba​x+ab​x=aba2−b2​:

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solve $\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}$ :

Solve $\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}$ :