C-05-Q072mediumsingle_mcq

A proper fraction has numerator $1$ less than denominator. Subtracting $2$ from numerator and adding $2$ to denominator gives $\dfrac{1}{6}$ . The fraction is—

a $\dfrac{2}{3}$
b $\dfrac{3}{4}$
c $\dfrac{4}{5}$
d $\dfrac{5}{6}$

ব্যাখ্যা

Taking the fraction as $\tfrac{n}{n+1}$ , the condition $\tfrac{n-2}{n+3}=\tfrac{1}{6}$ gives $6(n-2)=n+3$ , so $5n=15$ and $n=3$ . The fraction is therefore $\tfrac{3}{4}$ .

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

A proper fraction has numerator $1$ less than denominator. Subtracting $2$ from numerator and adding $2$ to denominator gives $\dfrac{1}{6}$ . The fraction is—

\dfrac{2}{3}

\dfrac{3}{4}

\dfrac{4}{5}

\dfrac{5}{6}

ব্যাখ্যা

Taking the fraction as $\tfrac{n}{n+1}$ , the condition $\tfrac{n-2}{n+3}=\tfrac{1}{6}$ gives $6(n-2)=n+3$ , so $5n=15$ and $n=3$ . The fraction is therefore $\tfrac{3}{4}$ .

A proper fraction has numerator 111 less than denominator. Subtracting 222 from numerator and adding 222 to denominator gives 16\dfrac{1}{6}61​. The fraction is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

A proper fraction has numerator 111 less than denominator. Subtracting 222 from numerator and adding 222 to denominator gives 16\dfrac{1}{6}61​. The fraction is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

A proper fraction has numerator $1$ less than denominator. Subtracting $2$ from numerator and adding $2$ to denominator gives $\dfrac{1}{6}$ . The fraction is—

A proper fraction has numerator $1$ less than denominator. Subtracting $2$ from numerator and adding $2$ to denominator gives $\dfrac{1}{6}$ . The fraction is—