C-05-Q046mediumsingle_mcqSolve abx+bax=a2−b2ab\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}bax+abx=aba2−b2:ax=a2−b2a2+b2x = \dfrac{a^2 - b^2}{a^2 + b^2}x=a2+b2ব্যাখ্যাFactoring xxx out of the left side gives x⋅a2+b2ab=a2−b2abx\cdot\dfrac{a^2+b^2}{ab}=\dfrac{a^2-b^2}{ab}x⋅aba. The common factor cancels, leaving .