C-05-Q046mediumsingle_mcqSolve abx+bax=a2−b2ab\dfrac{a}{b}x + \dfrac{b}{a}x = \dfrac{a^2 - b^2}{ab}bax+abx=aba2−b2:ax=a2−b2a2+b2x = \dfrac{a^2 - b^2}{a^2 + b^2}x=a2+b2a2−b2bx=a2+b2a2−b2x = \dfrac{a^2 + b^2}{a^2 - b^2}x=a2−b2a2+b2cx=a−ba+bx = \dfrac{a - b}{a + b}x=a+ba−bdx=a+ba−bx = \dfrac{a + b}{a - b}x=a−ba+bব্যাখ্যাFactoring xxx out of the left side gives x⋅a2+b2ab=a2−b2abx\cdot\dfrac{a^2+b^2}{ab}=\dfrac{a^2-b^2}{ab}x⋅aba2+b2=aba2−b2. The common factor ababab cancels, leaving x=a2−b2a2+b2x=\dfrac{a^2-b^2}{a^2+b^2}x=a2+b2a2−b2.