C-05-Q050mediumsingle_mcq

Solution set of $\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2$ is—

a $\{3\}$
b $\{-3\}$
c $\{1\}$
dempty

ব্যাখ্যা

Since both terms share the denominator $x-1$ , combine the numerators and cross-multiply to get a linear equation that solves to $x=3$ . This value does not make any denominator zero ( $x\neq 1$ ), so it is valid and the solution set is $\{3\}$ .

এই অধ্যায়ের আরও প্রশ্ন

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

Solution set of $\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2$ is—

\{3\}

\{-3\}

\{1\}

dempty

Solution set of x−2x−1−1x−1=2\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2x−1x−2​−x−11​=2 is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of x−2x−1−1x−1=2\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2x−1x−2​−x−11​=2 is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of $\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2$ is—

Solution set of $\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2$ is—