C-10-Q142mediumsingle_mcq16⋅sin60∘16 \cdot \sin 60^\circ16⋅sin60∘ equals—a838\sqrt{3}83 mb888 mc161616 md16316\sqrt{3}163 mব্যাখ্যাSince sin60∘=32\sin 60^\circ=\dfrac{\sqrt{3}}{2}sin60∘=23, we get 16×32=8316\times\dfrac{\sqrt{3}}{2}=8\sqrt{3}16×23=83 m.