C-10-Q114mediumsingle_mcq

Combining the two equations gives $x = ?$

a $12.5$ m
b $25$ m
c $50$ m
d $25\sqrt{3}$ m

ব্যাখ্যা

From the two relations $h=x\tan 60^\circ=x\sqrt{3}$ and $h=(x+25)\tan 30^\circ=\dfrac{x+25}{\sqrt{3}}$ , equating gives $3x=x+25$ . Solving yields $2x=25$ , so $x=12.5$ m.

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q115Then equals—
C-10-Q116The approximate height of the tower is—
C-10-Q117From the initial point , elevation of the minar top is . The distance to the foot equals—
C-10-Q118After moving m towards the minar, the new distance to the foot equals—
C-10-Q119Combined equations give—
C-10-Q120The approximate height of the minar is—
C-10-Q121The exact (rationalized) form equals—
C-10-Q122With initial distance to the tower and elevation , equals—
C-10-Q123After moving m back, equals—
C-10-Q124Solving the two equations gives

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

Combining the two equations gives $x = ?$

12.5

25

50

25\sqrt{3}

ব্যাখ্যা

From the two relations $h=x\tan 60^\circ=x\sqrt{3}$ and $h=(x+25)\tan 30^\circ=\dfrac{x+25}{\sqrt{3}}$ , equating gives $3x=x+25$ . Solving yields $2x=25$ , so $x=12.5$ m.

Combining the two equations gives x=?x = ?x=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Combining the two equations gives x=?x = ?x=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Combining the two equations gives $x = ?$

Combining the two equations gives $x = ?$