C-10-Q082mediumsingle_mcq

From the same triangle, $\sin 30^\circ$ equals—

a $\dfrac{CD}{BC}$
b $\dfrac{BD}{CD}$
c $\dfrac{BC}{CD}$
d $\dfrac{BD}{BC}$

ব্যাখ্যা

With the right angle at $B$ , the side $BD$ is opposite angle $C$ and $CD$ is the hypotenuse of triangle $BCD$ . Since sine equals opposite over hypotenuse, $\sin 30^\circ = \frac{BD}{CD}$ .

এই অধ্যায়ের আরও প্রশ্ন

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Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

From the same triangle, $\sin 30^\circ$ equals—

\dfrac{CD}{BC}

\dfrac{BD}{CD}

\dfrac{BC}{CD}

\dfrac{BD}{BC}

ব্যাখ্যা

With the right angle at $B$ , the side $BD$ is opposite angle $C$ and $CD$ is the hypotenuse of triangle $BCD$ . Since sine equals opposite over hypotenuse, $\sin 30^\circ = \frac{BD}{CD}$ .

From the same triangle, sin⁡30∘\sin 30^\circsin30∘ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From the same triangle, sin⁡30∘\sin 30^\circsin30∘ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From the same triangle, $\sin 30^\circ$ equals—

From the same triangle, $\sin 30^\circ$ equals—